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=155-16H^2
We move all terms to the left:
-(155-16H^2)=0
We get rid of parentheses
16H^2-155=0
a = 16; b = 0; c = -155;
Δ = b2-4ac
Δ = 02-4·16·(-155)
Δ = 9920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9920}=\sqrt{64*155}=\sqrt{64}*\sqrt{155}=8\sqrt{155}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{155}}{2*16}=\frac{0-8\sqrt{155}}{32} =-\frac{8\sqrt{155}}{32} =-\frac{\sqrt{155}}{4} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{155}}{2*16}=\frac{0+8\sqrt{155}}{32} =\frac{8\sqrt{155}}{32} =\frac{\sqrt{155}}{4} $
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